Substituir
-name '*"$DATETIME".log'
com
-name "*$DATETIME.log"
As aspas simples são muito strongs, as aspas duplas permitem $ VARIABLE dentro.
A execução do seguinte comando funciona conforme o esperado:
find /path/to/logs/ \( -type f -name '*20161005.log' \) -print0 | tar -czvf /path/to/backups/backup_logs_20161005.tar.gz --null -T -
Mas, tentando usar isso em um script bash, recebo um arquivo .tar.gz
vazio:
#!/bin/bash
now="$(date)"
printf "Current date and time: $now"
## working paths
LOGSPATH="/path/to/logs/"
BACKPATH="/path/to/backups/"
## date to work with
DATETIME='date -d "yesterday 13:00 " '+%Y%m%d''
## find files matching the working date and .tar.gz the result
printf "\nStarting yesterday logs backup, please wait..."
find "$LOGSPATH" \( -type f -name '*"$DATETIME".log' \) -print0 | tar -czvf "$BACKPATH"backup_logs_"$DATETIME".tar.gz --null -T -
printf "\ndone!"
## delete backup files
printf "\nRemoving logs from yesterday..."
find "$LOGSPATH" -type f -name '*"$DATETIME".log' -delete
printf "\ndone!\n"
Saída:
Current date and time: Thu Oct 6 16:14:29 WEST 2016
Starting yesterday logs backup, please wait...
done!
Removing logs from yesterday...
done!
O que eu sinto falta ao colocar esse comando em um script bash?