if [ -x "$(which curl)" ] ; then
echo "Utility ...... curl [ ok ]"
else
echo "Utility ...... curl [fail]"
s=1
fi
eu tenho um script no bash:
s=0
if [ -f /usr/bin/curl ] && [ -x /usr/bin/curl ] ; then
echo "Utility ...... curl [ ok ]"
else
echo "Utility ...... curl [fail]"
s=1
fi
if [ -f "/bin/grep" ] && [ -x "/bin/grep" ] ; then
echo "Utility ...... grep [ ok ]"
else
echo "Utility ...... grep [fail]"
s=1
fi
if [ -f "/usr/bin/expr" ] && [ -x "/usr/bin/expr" ] ; then
echo "Utility ...... expr [ ok ]"
else
echo "Utility ...... expr [fail]"
s=1
fi
if [ -f "/bin/sed" ] && [ -x "/bin/sed" ] ; then
echo "Utility ...... sed [ ok ]"
else
echo "Utility ...... sed [fail]"
s=1
fi
if [ $s -eq 0 ]; then
echo "All seems to be good. Let's play."
else
echo "Please install requirement util! "
fi
Eu quero escrever sem / usr / bin ou / bin. Eu quero escrever uma variável:
$ENV/curl
E outros ...
Como fazer isso.
Tags bash linux shell shell-scripting path