Como escrever este pseudocódigo onde condição

3

Esta questão é a extensão desta questão sobre listar questões de diretórios . Eu tenho um problema que eu preciso entender a seção original do texto.

Saída atual

ondevocêvêasegundaperguntanãofazsentido.FoiincluídonaarteritedeTakayasusubsectionnodiretórioRheumatology:

\subsection{Takayasuarteritis}\begin{question}{Yougetapatient.Whatdoyounoticefirstinthispatient?}Absenceofperipheralpulse.\end{question}Loremipsum.\begin{question}{WhatwasthefirstTakayasucase?}YoungwomaninAsiawithredvesselsintheeye.Sospecialeyediagnosisdone.Affectseye.\end{question}

emqueasaídaatualéporesseexcelente código

\section{Rheumatology}  

\begin{question}
{You get a patient. 
What do you notice first in this patient?}
Absence of peripheral pulse.
\end{question}

\begin{question}
{What was the first Takayasu case?}
Young woman in Asia with red vessels in the eye. 
So special eye diagnosis done. 
Affects eye.
\end{question}

mas gostaria que fosse

\section{Rheumatology}  

\subsection{Takayasu arteritis}

\begin{question}
{You get a patient. 
What do you notice first in this patient?}
Absence of peripheral pulse.
\end{question}

\begin{question}
{What was the first Takayasu case?}
Young woman in Asia with red vessels in the eye. 
So special eye diagnosis done. 
Affects eye.
\end{question}

Minha proposta é incluir subseções se houver perguntas na subseção.

Meu pseudocódigo

Look for the environment \begin{question}...\end{question}.
See the subsection of the question (it locates above the question). 
   If there is no subsection, leave blank. 
   If there are many questions within one subsection, put only one subsection. 

Código de Terdon

#!/usr/bin/env bash

## avoid errors if a directory has no *tex files
shopt -s nullglob

directories=("Cardiology" "Rheumatology" "Surgery");

## Change this to set whichever options you want.
printf "%s\n%s\n" "\documentclass{YOURCLASS}" "\begin{document}"

for directory in ${directories[@]}
do
    ## Reset the counter, avoid empty sections.
    c=0;
    for file in "$directory"/*tex
    do
        let c++
        [ "$c" -eq 1 ] && printf "\n%s\n" "\section{$directory}"
        ## Extract the wanted lines
        perl -lne '$a=1 && print "" if /\begin{question}/; 
                  print if $a==1;
                  $a=0 if /\end{question}/;' "$file" 
        echo ""
    done
done
echo "\end{document}"

onde eu acho que a lógica dessas linhas deve ser alterada

        ## Extract the wanted lines
        perl -lne '$a=1 && print "" if /\begin{question}/; 
                  print if $a==1;
                  $a=0 if /\end{question}/;' "$file" 
        echo ""

que usa um regex para encontrar todas as perguntas em um arquivo E ignora as subseções das perguntas.

Exemplo de dados (pouco diferente do último caso!)

\subsection{Takayasu arteritis}

\begin{question}
{You get a patient. 
What do you notice first in this patient?}
Absence of peripheral pulse.
\end{question}

\begin{question}
{What was the first Takayasu case?}
Young woman in Asia with red vessels in the eye. 
So special eye diagnosis done. 
Affects eye.
\end{question}


Fever of unknown origin can be used when you do not know what is causing the disease. 

% Show cases in MedScape and ask class. 

Aneurysms. 


\subsubsection{Treatment}

\begin{question}
{What you should always include in Takayasu treatment? 
What are the symptoms?}
Blood pressure.
Aneurysms which will burst without treatment. 
So blood pressure decreasing drugs like beta blockers along in combination with other drugs.
\end{question}

\begin{question}
{When is the checkup of the Takayasu arteritis?} 
Only once per year. 
You could expect every month like normally in this kind of diseases.
But only once per year.
\end{question}

onde você pode ignorar subsubsections no aplicativo.

Como você pode escrever o pseudocódigo?

Bug no código de Terdon 14.10.2014 encontrado

Exemplo de dados que causam o bug

\subsection{3}
A 55 y.o male says that for the last year ... 

\begin{question}
{What is the pathogenetic mechanism of his complains?} 
\end{question}

que analisado pelo código de Terdon dá exatamente o mesmo resultado que está errado, já que a sentença A 55 y.o ... não deveria estar mais lá no resultado final. Se houver uma entrada entre a subseção e o texto do corpo, corrija a saída. No entanto, isso não pode ser assumido.

A causa deste bug são os símbolos do Windows, movidos aqui .

    
por Léo Léopold Hertz 준영 05.10.2014 / 22:54

2 respostas

2

Eu ia estender meu código original, mas está chegando a um ponto em que é muito mais fácil simplesmente reimplementar tudo em Perl diretamente:

#!/usr/bin/env perl

## This is the path to the target  directories
my $path="/Users/Masi/Dropbox/";

## The target directories
my @directories=("Cardiology","Rheumatology","Surgery");

## Iterate over the directories
foreach my $dir (@directories) {
    my $dd=0;
    ## Read the current directory
    opendir (my $DIR, "$path/$dir");
    ## Find all files in this directory
    while (my $file = readdir($DIR)) {
        ## Reset the counter
        my $c=0;
        ## Skip any files that aren't .tex
        next unless $file =~ /\.tex$/;

        ## Open the file
        open(my $fh,"$path/$dir/$file");

        while (<$fh>) {
            ## Get the subsection. $_ is the current line.
            $sub="$_" and $n=0 if /\subsection{/;
            ## If this line is a question
            if (/\begin{question}/) {
                ## If this counter is 0, this is the first file
                ## of this directory, so print the section
                ## Print the section name
                if ($dd==0) {
                    print "\section{$dir}\n\n";
                    $dd++;
                } 
                ## If this counter is 0, this is the first question
                ## of this subsection, so print the subsection line
                print "$sub\n" if $n==0;

                $n++;
                ## Increment the counter, we want these lines
                $c++;
                ## And print
                print;
            }
            else {
                ## Print lines if the counter is 1
                print if $c==1;
                ## reset the counter to 0
                print "\n" and $c=0 if /\end{question}/;
            }
        }
        print "\n";
    }

}

Observe que isso ignora as subsubsections, mas seria fácil modificá-lo para incluí-las.

    
por 06.10.2014 / 04:55
0

Extensão ou melhoria do código de Terdon com base na lógica desta resposta

#!/usr/bin/env perl

## This is the path to the target  directories
my $path="/Users/Masi/Dropbox/";
chdir $path or die "cannot chdir '$path'";

## Iterate over the directories
foreach my $dir (
    "Cardiology", "Pathophysiology", "Patology and Biopsy", "Physiology",
    "Propedeutics", "Radiology", "Rheumatology", "Surgery"
)
{
    my $dd=0;
    ## Read the current directory
    opendir my $DIR, $dir or die "cannot opendir '$dir'";

    ## Find all files in this directory
    while (my $file = readdir($DIR)) {
        ## Reset the counter
        my $c=0;
        ## Skip any files that aren't .tex
        next unless $file =~ /\.tex$/;

        ## Open the file
        open(my $fh,"$path/$dir/$file");

        while (<$fh>) {
            ## Get the subsection. $_ is the current line.
            $sub="$_" and $n=0 if /\subsection{/;
            ## If this line is a question
            if (/\begin{question}/) {
                ## If this counter is 0, this is the first file
                ## of this directory, so print the section
                ## Print the section name
                if ($dd==0) {
                    print "\section{$dir}\n\n";
                    $dd++;
                }
                ## If this counter is 0, this is the first question
                ## of this subsection, so print the subsection line
                print "$sub\n" if $n==0;

                $n++;
                ## Increment the counter, we want these lines
                $c++;
                ## And print
                print;
            }
            else {
                ## Print lines if the counter is 1
                print if $c==1;
                ## reset the counter to 0
                print "\n" and $c=0 if /\end{question}/;
            }
        }
        print "\n";
    }
    closedir $DIR  or die "cannot closedir '$dir'";
}

onde adicionei alguns erros de gerenciamento.

    
por 13.04.2017 / 14:36