Como executar um job a cada 6 horas a partir das 3:00 usando runwhen

Question

Eu tento fazer executar quando realizar um trabalho a cada 6 horas, começando às 3:00 da manhã.

(Como) Isso pode ser feito?

    

Answer 1

encontrou uma solução - se alguém estiver interessado ...

#!/bin/sh -e

RUNWHEN=",H/6"

# The constraint string consists of a sequence of unit constraints. Each unit
# constraint consists of a comma, one of the following letters indicating which
# unit is constrained:
#
#     * y: year.
#     * m: month (in the range 1-12).
#     * d: day of the month (in the range 1-28, 1-29, 1-30, or 1-31, as
#          appropriate for the month in question).
#     * w: day of the week (in the range 0-6, with 0 representing Sunday).
#     * H: hour of the day (in the range 0-23).
#     * M: minute of the hour (in the range 0-59).
#     * S: second of the minute (in the range 0-59). 
#
# and finally one of the following:
#
#     * =n: matches times when the given unit is exactly n.
#     * -n: matches times when the given unit is exactly m, where m+n is one
#           more than the largest value of the unit. (For example, n+m=24 for H,
#           so ,H-1 is equivalent to ,H=23.
#     * /n: matches times when the given unit is divisible by n. 

exec 2>&1 \
rw-add n d1S now1s \
rw-match \$now1s $RUNWHEN wake \
## here comes the interesting part
rw-add \$wake d3H wake \
sh -c '
  echo "@$wake" | tai64nlocal | sed "s/^/next run time: /"
  exec "$@"' arg0 \
rw-sleep \$wake \
thescript