Saída na execução do PHP a partir da linha de comando

Question

Ao executar o PHP na CLI, com o mesmo script simultaneamente no Ubuntu Linux, eu tenho isto:

[1]   Done                    php /var/www/html/deletebadsubjtermsnew.php 150 2 > /var/www/html/deletebadsubjtermsnew8Feb17-R3-2.log.txt
[2]   Done                    php /var/www/html/deletebadsubjtermsnew.php 150 3 > /var/www/html/deletebadsubjtermsnew8Feb17-R3-3.log.txt
[3]   Done                    php /var/www/html/deletebadsubjtermsnew.php 150 4 > /var/www/html/deletebadsubjtermsnew8Feb17-R3-4.log.txt
[4]   Done                    php /var/www/html/deletebadsubjtermsnew.php 150 5 > /var/www/html/deletebadsubjtermsnew8Feb17-R3-5.log.txt
[5]-  Done                    php /var/www/html/deletebadsubjtermsnew.php 150 6 > /var/www/html/deletebadsubjtermsnew8Feb17-R3-6.log.txt
[6]+  Done                    php /var/www/html/deletebadsubjtermsnew.php 150 7 > /var/www/html/deletebadsubjtermsnew8Feb17-R3-7.log.txt

O que é o - e + para próximo de [5] e [6]?

    

Answer 1

Do homem bash:

In output pertaining to jobs (e.g., the output of the jobs command), the current job is always flagged with a +, and the previous job with a -.

O trabalho + chegará ao primeiro plano com fg