Comando Unix para encontrar uma palavra no arquivo [closed]

Question

Estamos tendo um script de shell. No script de shell, queremos descobrir se o arquivo file.log tem palavra como MB . Em caso afirmativo, armazene-o na variável v_name no shell script, se não houver essa palavra, então v_name deve estar vazio.

Observação: O file.log conterá no máximo uma palavra MB .

    

Answer 1

Se file.log contiver a string MB , atribua o texto MB à variável v_name :

grep -q MB file.log && v_name=MB

Ref: página man para o grep

    

Answer 2

Um comando unix para encontrar uma palavra nos arquivos é

grep

$ man grep | grep -A 5 DESCRIPTION
DESCRIPTION
   grep  searches the named input FILEs (or standard input if no files are named, or if a single hyphen-minus (-) is given as file name) for lines containing a
   match to the given PATTERN.  By default, grep prints the matching lines.

   In addition, three variant programs egrep, fgrep and rgrep are available.  egrep is the same as grep -E.  fgrep is the same as grep -F.  rgrep is  the  same
   as grep -r.  Direct invocation as either egrep or fgrep is deprecated, but is provided to allow historical applications that rely on them to run unmodified.

    

Answer 3

v_name=$(grep -P "\d+\.\d+ MB")

dá a sua variável, e. "92,29 MB"

    

Answer 4

#!/bin/bash

# $1 = pattern
# $2 = file name to search in
# did not write or test script to handle wild cards in $2

# -i option in grep is case insensitive, use just -l if you care about case

vname='grep -li $1 $2'

if [ -z "$vname" ]; then
   echo "vname is empty"
else
   echo "vname is " $vname
   # set vname to pattern searched for
   vname=$1
   echo "vname is " $vname
fi