bash script bloqueado em if statement quando executado

0

Não sou especialista em scripts bash. Eu estou tentando entender por que um script bash parece parar sua execução em uma instrução if . Eu adicionei instruções echo nos scripts.

Eu tenho um primeiro lote chamado make.sh :

#!/bin/bash

export OPENSHIFT_RUNTIME_DIR=${OPENSHIFT_HOMEDIR}/app-root/runtime
export ROOT_DIR=${OPENSHIFT_RUNTIME_DIR}    #CARTRIDGE
export LIB_DIR=${ROOT_DIR}/lib
export CONF_DIR=${OPENSHIFT_REPO_DIR}/conf

export DIST_PHP_VER=5.6.11

pushd ${OPENSHIFT_REPO_DIR}/misc

chmod +x make_php
echo 'before source make_php'
source make_php
echo 'before check_all'
check_all

popd

O script make_php é:

#!/bin/bash

function install_php() {
    ...
}

function check_php() {
    echo 'entering check php'
    if [[ -x $OPENSHIFT_RUNTIME_DIR/bin/php-cgi ]] ; then
    echo 'entering check php between if'
    if [[ "'$OPENSHIFT_RUNTIME_DIR/bin/php-cgi'" =~ "${DIST_PHP_VER}" ]] ; then
        echo 'leaving check php return 0'
        return 0
    fi
    fi

    echo "Check PHP ${DIST_PHP_VER} Failed. Start installing"
    install_php
}

function check_composer() {

    echo 'entering check composer'
    ...
    echo 'leaving check composer'

}

function check_all() {

    echo 'entering check all'
    check_php
    echo 'after check php'
    check_composer
    echo 'after composer'

}

Quando executo ./make.sh , a saída é:

before source make_php
entering check all
entering check php
entering check php between if

e eu não obtenho o prompt de volta, eu tenho que CTRL-C

O que poderia estar causando esse problema? E como resolver isso?

UPDATE

Quando eu vou para $ OPENSHIFT_RUNTIME_DIR / bin / e executo o php-cgi, o programa bloqueia ... Isso pode explicar o problema.

    
por Jérôme Verstrynge 23.07.2015 / 21:37

1 resposta

2

Parece que o script estava executando o php como um aplicativo, em vez de tentar obter o número da versão. Você deve conseguir corrigi-lo alterando a linha para ler:

if [[ "'$OPENSHIFT_RUNTIME_DIR/bin/php-cgi --version'" =~ "${DIST_PHP_VER}" ]] ; then

O =~ test é uma correspondência de expressão regular, parte do bash. Na página do manual bash (1) :

   An  additional  binary operator, =~, is available, with the same prece‐
   dence as == and !=.  When it is used, the string to the  right  of  the
   operator  is  considered  an  extended  regular  expression and matched
   accordingly (as in regex(3)).  The return value  is  0  if  the  string
   matches  the  pattern,  and  1 otherwise.  If the regular expression is
   syntactically incorrect, the conditional expression's return  value  is
   2.   If the shell option nocasematch is enabled, the match is performed
   without regard to the case of alphabetic characters.  Any part  of  the
   pattern  may  be  quoted to force the quoted portion to be matched as a
   string.  Bracket expressions in regular  expressions  must  be  treated
   carefully,  since normal quoting characters lose their meanings between
   brackets.  If the pattern is stored in a shell  variable,  quoting  the
   variable expansion forces the entire pattern to be matched as a string.
   Substrings matched by parenthesized subexpressions within  the  regular
   expression  are  saved in the array variable BASH_REMATCH.  The element
   of BASH_REMATCH with index 0 is the portion of the string matching  the
   entire regular expression.  The element of BASH_REMATCH with index n is
   the portion of the string matching the nth parenthesized subexpression.
    
por 23.07.2015 / 22:18