Vamos criptografar a falha ao solicitar certificado no Webmin / Virtualmin

Question

Estou tentando fazer com que o Encrypt funcione no servidor Ubuntu 16.04 - > LAMP - > Webmin - > Virtualmin No entanto, recebo um erro ao solicitar um certificado. Eu usei estes comandos para instalar:

apt-get update
apt-get -y install git bc
git clone https://github.com/letsencrypt/letsencrypt /opt/letsencrypt
/opt/letsencrypt/letsencrypt-auto --help

Preencha este caminho dentro de Webmin - > Configuração Webmin - > Link de configuração do módulo ou botão no canto superior esquerdo - > Caminho completo para o cliente "Vamos criptografar o cliente"
/ opt / letsencrypt /

Mensagem de erro:

Parsing account key...
Parsing CSR...
Registering account...
Already registered!
Verifying domain1234.com...
Traceback (most recent call last):
  File "/usr/share/webmin/webmin/acme_tiny.py", line 202, in <module>
    main(sys.argv[1:])
  File "/usr/share/webmin/webmin/acme_tiny.py", line 198, in main
    signed_crt = get_crt(args.account_key, args.csr, args.acme_dir, log=LOGGER, CA=args.ca)
  File "/usr/share/webmin/webmin/acme_tiny.py", line 122, in get_crt
    resp = urlopen(wellknown_url)
  File "/usr/lib/python2.7/urllib2.py", line 154, in urlopen
    return opener.open(url, data, timeout)
  File "/usr/lib/python2.7/urllib2.py", line 429, in open
    response = self._open(req, data)
  File "/usr/lib/python2.7/urllib2.py", line 447, in _open
    '_open', req)
  File "/usr/lib/python2.7/urllib2.py", line 407, in _call_chain
    result = func(*args)
  File "/usr/lib/python2.7/urllib2.py", line 1228, in http_open
    return self.do_open(httplib.HTTPConnection, req)
  File "/usr/lib/python2.7/urllib2.py", line 1201, in do_open
    r = h.getresponse(buffering=True)
  File "/usr/lib/python2.7/httplib.py", line 1136, in getresponse
    response.begin()
  File "/usr/lib/python2.7/httplib.py", line 453, in begin
    version, status, reason = self._read_status()
  File "/usr/lib/python2.7/httplib.py", line 417, in _read_status
    raise BadStatusLine(line)
httplib.BadStatusLine: ''

    

Answer 1

O caminho completo inclui o nome do arquivo, por exemplo: /x/y/filename.pls No meu caso com Let's Encrypt o caminho completo é: / opt / letsencrypt / certbot-auto